Interview question

How does try-catch-finally work in Java, and when does finally NOT execute? Java में try-catch-finally कैसे काम करता है, और finally कब execute नहीं होता?

Answer

public int divide(int a, int b) {
    try {
        return a / b;
    } catch (ArithmeticException e) {
        System.out.println('Caught: ' + e.getMessage());
        return -1;
    } finally {
        System.out.println('finally always runs');  // runs even with a return above
    }
}

divide(10, 2);  // prints 'finally always runs', returns 5
divide(10, 0);  // prints 'Caught: / by zero', 'finally always runs', returns -1

// finally runs even when try/catch has a return statement
public int example() {
    try {
        return 1;
    } finally {
        System.out.println('finally runs before the return completes');
    }
}

// Rare cases where finally does NOT execute:
// 1. JVM crashes or is killed (System.exit(), power failure)
public void withExit() {
    try {
        System.exit(0);  // finally will NOT run
    } finally {
        System.out.println('This never prints');
    }
}
// 2. Infinite loop or deadlock inside try block - never reaches finally
// 3. The thread executing try is forcibly killed (Thread.stop() - deprecated)

public int divide(int a, int b) {
    try {
        return a / b;
    } catch (ArithmeticException e) {
        System.out.println('Caught: ' + e.getMessage());
        return -1;
    } finally {
        System.out.println('finally हमेशा चलता है');
    }
}

divide(10, 2);
divide(10, 0);

public int example() {
    try {
        return 1;
    } finally {
        System.out.println('return पूरा होने से पहले finally चलता है');
    }
}

// finally न चलने के rare cases:
// 1. JVM crash या System.exit()
public void withExit() {
    try {
        System.exit(0);  // finally नहीं चलेगा
    } finally {
        System.out.println('यह कभी नहीं print होगा');
    }
}
// 2. try में infinite loop
// 3. Thread forcibly kill हो जाए

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